what mass of oxygen gas reacts with 5000g of ZnS to give ZnO and SO4?

The balanced chemical equation is as follows:

`2ZnS + 5O_2 -> 2ZnO + 2SO_4` .

We want to know the mass of oxygen enough to completely react with 5000 g of ZnS. As seen in the balanced chemical equation, 2 moles of ZnS react with 5 moles of molecular oxygen. Therefore, for every 2 moles of ZnS, we need 5 moles of oxygen. For every 1 mole of ZnS, we need 5/2 moles of oxygen.

The number of moles of ZnS can be calculated as follows:

n = mass / molar mass = 5000 g / 97.474 g/ mol = 51.30 moles

We need 5/2 as much moles of oxygen: 51.30*5/2 = 128.24 moles of oxygen.

The mass of oxygen, then, can be calculated as follows:

mass = 128.24 moles O2 * 32 grams/mol O2 = 4,103.66 grams.

Therefore, 4103.66 grams of oxygen is needed to react with 5000 grams of ZnS to produce the products.

This problem can also be solved using stoichiometry as follows:

mass O2 = 5000g ZnS * 1mol ZnS / 97.474 g ZnS * 5 mol O2 / 2mol ZnS * 32 g O2 / mol O2

mass O2 = 4103.66 grams