You need to evaluate the binomial coefficient, using the next formula, such that:
`nCk = (n!)/(k!(n-k)!)`
Replacing 8 for n and 6 for k yields:
`8C6 = (8!)/(6!(8-6)!) => 8C6 = (8!)/(6!*2!)`
Notice that `8! = 1*2*3*4*5*6*7*8 => 8! = 6!*7*8`
` 8C6 = (6!*7*8)/(6!*2!) => 8C6 = (7*8)/(2!) => 8C6 = (7*8)/(1*2)`
Hence, evaluating the binomial coefficient yields 8C6 = 28.
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