Take note that pressure is defined as force per unit area.
`P = F/A`
(where P is the pressure, F is the force applied and A is the surface area where the force is applied)
Plugging in the values of P and A, the formula becomes:
`10 (l b s)/( i n ^2) = F/(0.001 i n ^2)`
Isolating the F, it yields:
`10(l b s)/(i n ^2) * 0.001 i n ^2 = F`
`0.01 lbs = F`
Therefore, 0.01 lbs of force is applied to pop the balloon.
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