Sunday, April 24, 2011

Find the area of the triangle with the vertices at the points (-6,6), (5,-1), (5,6).

Another way to calculate the area of this triangle is by noticing that two of the given points have the same x-coordinates, and two of the given points have the same y-coordinates. This means one side of the triangle is parallel to the x-axis, and another side is parallel two the y-axis. These sides are perpendicular to each other, so this is a right triangle. The area of the right triangle is half of the product of the perpendicular sides (a special case of the more general formula for the area of a triangle: area = 1/2 of base times height.)


The length of the side with the ends at the vertices (-6,6) and (5,6) (the side parallel to the x-axis) is


`l_1 = 5 - (-6) = 11`


The length of the side with the ends at the vertices (5, -1) and (5,6) (the side parallel to the y-axis) is


`l_2 = 6 - (-1) = 7`


So the area of the triangle is


`A = 1/2*l_1*l_2 = 1/2*77 = 38.5` .


The area of the triangle is 38.5.

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