You need to evaluate the binomial coefficient, using the next formula, such that:
`((n),(k)) = (n!)/(k!(n-k)!)`
You need to replace 10 for n and 6 for k, such that:
`((10),(6)) = (10!)/(6!(10-6!) )=> ((10),(6) )= (10!)/(6!4!)`
Notice that `10! = 6!*7*8*9*10`
` (10!)/(6!4!) = (6!*7*8*9*10)/(6!4!) => ((10),(6)) =(7*8*9*10)/(1*2*3*4) = 210`
Hence, evaluating the binomial coefficient yields `((10),(6)) = 210.`
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