You need to use the binomial formula, such that:
`(x+y)^n = sum_(k=0)^n ((n),(k)) x^(n-k) y^k`
You need to replace 2x for x, y for y and 3 for n, such that:
`(2x+y)^3 = 3C0 (2x)^3+3C1 (2x)^2*(y)^1+3C2 (2x)^1*(y)^2+3C3(y)^3`
By definition, nC0 = nCn = 1, hence `3C0 = 3C3 = 1.`
By definition nC1 = nC(n-1) = n, hence `3C1 = 3C2 = 3.`
`(2x+y)^3 = 8x^3+12x^2*y+6x*y^2+y^3`
Hence, expanding the complex number using binomial theorem yields the simplified result `(2x+y)^3 = 8x^3+12x^2*y+6x*y^2+y^3.`
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