`(3, sqrt(3)), (6, -2sqrt(3))` Find the inclination 'theta' (in radians and degrees) of the line with slope m.

Given coordinates are `(3,sqrt(3)),(6,-2sqrt(3))`

Slope (m)=`(y_2-y_1)/(x_2-x_1)`

Plug in the given coordinates in the above formula,

`m=(-2sqrt(3)-sqrt(3))/(6-3)`

`m=(-3sqrt(3))/(3)`

`m=-sqrt(3)`

So the angle of inclination(`theta` )=`arctan(-sqrt(3))`

`theta=-60^@` 

or`theta=360-60=300^@`

Use the conversion `360^@` = `2pi` radians

`:.300^@=((2pi)/360)*300`

` ` `=(5pi)/3`

Answer: `300^@`

and  `(5pi)/3` radians