You need to evaluate the binomial coefficient, using the next formula, such that:
`((n),(k)) = (n!)/(k!(n-k)!)`
You need to replace 10 for n and 6 for k, such that:
`((10),(4)) = (10!)/(4!(10-4)!) )=> ((10),(4) )= (10!)/(4!6!)`
Notice that `10! = 6!*7*8*9*10`
`((10),(4)) = (6!*7*8*9*10)/(6!4!) => ((10),(4)) =(7*8*9*10)/(1*2*3*4) = 210`
Hence, evaluating the binomial coefficient yields `((10),(4)) = 210.`
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