`(sqrt(2), 2), (0, 1)` Find the inclination 'theta' (in radians and degrees) of the line with slope m.

Given `(sqrt2, 2), (0, 1)`

Find the slope using the formula

`m=(y_2-y_1)/(x_2-x_1)`

`m=(1-2)/(0-sqrt2)=(-1)/(-sqrt2)=1/sqrt2` 

The slope of the line `1/sqrt2.`

Find the inclination.

`theta=arctan(1/sqrt2)=35.3^@=.6155` radians.

The inclination is 35.3 degrees or .6155 radians.