1 g of sodium is allowed to react with 15 g of chlorine. Sodium is consumed completely and 2.54 g of sodium chloride is formed. When 1 g of...

Sodium reacts with chlorine to form sodium chloride as per the following equation:

`2Na + Cl_2 -> 2NaCl`

Here, 2 moles of sodium reacts with 1 mole of chlorine to generate 2 moles of sodium chloride.

The molar masses of sodium (Na), chlorine (Cl2) and sodium chloride (NaCl) are 23 g/mole, 71 g/mole and 58.5 g/mole, respectively.

Here, 1 g of chlorine reacts with 15 g of sodium and is consumed completely. 

Using the molar mass of chlorine, 1 g of chlorine = 1/71 moles

Since 1 mole of chlorine generates 2 moles of sodium chloride, 1/71 moles will generate 2/71 moles of sodium chloride.

or, 2/71 x 58.5 g sodium chloride = 1.65 g sodium chloride.

The other information about 1 g sodium being completely consumed to produce 2.54 g sodium chloride is not required for solving this numerical. However, that data can also be tested similarly.

Hope this helps.