A Galvanic cell based on the reaction between silver ions and copper is constructed. The chemical equation for the reaction is: 2Ag+(aq) +...

A. In the galvanic cell described by the equation

`2Ag^+_(aq) + Cu_((s)) -> 2Ag_((s)) + Cu^(2+)_(aq)`

copper is being oxidized and silver is being reduced. 

Here's how this can be determined:

• Copper goes from Cu with an oxidation number of 0 to Cu2+ with an oxidation number of +2. Each copper atom loses two electrons. The species that loses electrons and has an increase in oxidation number is oxidized.


• Silver goes from Ag+ with an oxidation number of +1 to Ag with an oxidation number of 0. Each silver atom gains one electron. the species that gains electrons and has a decrease in oxidation number is reduced. 

B. The anode is the electrode at which oxidation takes place and the cathode is the electrode at which reduction takes place. In this cell copper is the anode because it is being oxidized. Silver metal is plating onto the cathode as silver is reduced. It's likely that the cathode is a strip of silver, but we're not told that. There could be an inert cathode that conducts the electrons from the circuit to the silver ions in solution. 

C. The cathode is gaining mass as the reaction proceeds. As silver ions from solution gain electrons from the cathode, they attach to the cathode creating layers of silver metal on its surface.

D. The voltage produced by three of these cells connected in series would be:

3 x (1.1 V) = 3.3 V

Voltage across a series circuit is the sum of the voltages across each device in the circuit.  

Here are a couple of mnemonics to help you with electrochemistry:
 

LEO the lion says GER (Lose Electrons, Oxidation and Gain Electrons, Reduction)

red cat - reduction occurs at the cathode

an ox - oxidation occurs at the anode